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[PHP] Passing a URL through a URL
| Posted by krissauquillo, 12-06-2007, 09:45 PM |
| I can't seem to find a solution to this, so I was hoping someone here would know..
The problem is when I use:
http://domain.com/?link=http://test.net/?a=1&b=2
And then use $_GET['link'] to retrieve the variable in PHP, I get:
http://domain.com/?link=http://test.net/?a=1
The ampersand (&) is being parsed as a cut-off mark. Anyone know how I can fix it?
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| Posted by Annex, 12-06-2007, 09:56 PM |
| Just use the hexadecimal notation for the amprisan, which is %26 so your link would be
http://domain.com/?link=http://test....=1%26b=2%26c=3
The browser will parse the %26 as an amprisan, only difficulty is replacing all links.
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| Posted by foobic, 12-06-2007, 09:58 PM |
| http://au.php.net/manual/en/function.urlencode.php
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| Posted by Codebird, 12-08-2007, 11:32 AM |
| use the %26 and then str_replace("%26", "&", $_GET['link']);
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| Posted by Harzem, 12-08-2007, 11:35 AM |
| It is called "urlencode", as foobic said.
|
| Posted by Czaries, 12-11-2007, 02:53 PM |
| Yes, just use the built-in "urlencode" function... No sense in creating your own function that will run slower than native C code.
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